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17x^2+70x-552=0
a = 17; b = 70; c = -552;
Δ = b2-4ac
Δ = 702-4·17·(-552)
Δ = 42436
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{42436}=206$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-206}{2*17}=\frac{-276}{34} =-8+2/17 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+206}{2*17}=\frac{136}{34} =4 $
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